Crop coords can be outside of image#166

I've noticed that sometimes image can be outside of source image, code below, you can test it. I've also make some quick fixes, I hope you know how to do it better ```python data = [ (663, 2495, 185, 867, 327, 354), (612, 1020, 13, 280, 26, 33), (612, 1020, 979, 282, 24, 34), (612, 1020, 1003, 169, 16, 21), (612, 1020, 993, 351, 26, 44), (612, 1020, 996, 271, 21, 26), (612, 1020, 9, 382, 30, 49), (612, 1020, 0, 231, 14, 27), ] crop = Cropper() for item in data: pos = crop.crop_positions(*item) print(*item) print(pos) print('---') ``` Output: ``` 663 2495 185 867 327 354 [690, 1398, -5, 702] --- 612 1020 13 280 26 33 [263, 329, -7, 59] --- 612 1020 979 282 24 34 [265, 333, 957, 1025] --- 612 1020 1003 169 16 21 [167, 191, 999, 1022] --- 612 1020 993 351 26 44 [349, 396, 982, 1029] --- 612 1020 996 271 21 26 [267, 300, 989, 1023] --- 612 1020 9 382 30 49 [367, 445, -15, 63] --- 612 1020 0 231 14 27 [231, 258, -6, 20] --- ``` Fixes: 1. Try to save aspect ratio ```python def _crop_positions(self, imgh, imgw, x, y, w, h): if h1 < 0: h1, h2 = 0, h2 + abs(h1) if v1 < 0: v1, v2 = 0, v2 + abs(v1) if h2 > imgw: h1, h2 = h1 + abs(h2 - imgw), imgw if v2 > imgh: v1, v2 = v1 + abs(v2 - imgh), imgh ``` 2. Just crop and lose aspect ratio ```python def _crop_positions(self, imgh, imgw, x, y, w, h): pos = self._clamp(v1, 0, imgh), self._clamp(v2, 0, imgh), self._clamp(h1, 0, imgw), self._clamp(h2, 0, imgw) @staticmethod def _clamp(n: int, min_n: int, max_n: int): return max(min(max_n, n), min_n) ```